(x^2-2x-4)(x^2-3x-5)=x

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Solution for (x^2-2x-4)(x^2-3x-5)=x equation: 



(x^2-2x-4)(x^2-3x-5)=x

We move all terms to the left:

(x^2-2x-4)(x^2-3x-5)-(x)=0

We add all the numbers together, and all the variables

-1x+(x^2-2x-4)(x^2-3x-5)=0

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